sync: 01-03
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Записи/1 СЕМ/Вышмат/math-200/Untitled.md
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Записи/1 СЕМ/Вышмат/math-200/Untitled.md
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$y=2^{\arctan(\sqrt{ x })}$
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$y=p'(g(f(x)))\cdot g'(f(x))\cdot f'(x)$
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$p'=2^{\arctan(\sqrt{ x })}\cdot \ln 2$
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$g'=\dfrac{1}{1+x}$
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$f'=\dfrac{1}{2\sqrt{ x }}$
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$y'=2^{\arctan(\sqrt{ x })}\cdot \ln 2\cdot\dfrac{1}{1+x}\cdot\dfrac{1}{2\sqrt{ x }}=\dfrac{2^{\arctan \sqrt{ x }}\ln 2}{2\sqrt{ x }(1+x)}$
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