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snus xD
2026-02-25 14:01:01 +03:00
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$\int_{a}^{+\infty} f(x) \, dx=\lim_{ b \to +\infty }\int_{a}^{b} f(x) \, dx$
$f(x)=\frac{1}{x^2}$
$\int_{1}^{+\infty} \frac{1}{x^2} \, dx=\frac{1}{x}|_{1}^{+\infty}=-\frac{1}{+\infty}-\left( -\frac{1}{1} \right)=1$